[솔루션]확률과입문 a fisrt course in probability 7판
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(c) 4!3! = 144
확률,솔루션,입문,7판,probability
4!4!2!
7! = 1260
numbers 1, …, 20 and so there are 20! different possible assignments.
(d) 6 ⋅ 3 ⋅ 2 ⋅ 2 ⋅ 1 ⋅ 1 = 72
2!2!
6!4!
출판사 & 저자 : sheldon ross
설명
that order, we see by the generalized basic principle that there are 2 ⋅ 1 ⋅ 2 ⋅ 1 = 4 possibilities.
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(b)
(d)
(c) 5!4! = 2,880
6. Each kitten can be identified by a code number i, j, k, l where each of i, j, k, l is any of the
1. (a) By the generalized basic principle of counting there are
(b) 2 ⋅ 3! ⋅ 3! = 72
5. There were 8 ⋅ 2 ⋅ 9 = 144 possible codes. There were 1 ⋅ 2 ⋅ 9 = 18 that started with a 4.
4. There are 4! possible arrangements. By assigning instruments to Jay, Jack, John and Jim, in
(12)! = 27,720
순서
26 ⋅ 26 ⋅ 10 ⋅ 10 ⋅ 10 ⋅ 10 ⋅ 10 = 67,600,000
3. An assignment is a sequence i1, …, i20 where ij is the job to which person j is assigned. Since
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title : 확률과 입문 a fisrt course in probability 7판
(b) 2 ⋅ 7! = 10,080
[솔루션]확률과입문 a fisrt course in probability 7판
7! = 1260
(b) 26 ⋅ 25 ⋅ 10 ⋅ 9 ⋅ 8 ⋅ 7 ⋅ 6 = 19,656,000
제목 : 확률과 입문 a fisrt course in probability 7판 출판사 & 저자 : sheldon ross 잘못된 자료가 있을시 환불요청 하시면 환불을 받으실수 있습니다.
2!2!
(c)
7. (a) 6! = 720
레포트 > 공학,기술계열
11! = 34,650
numbers from 1 to 7. The number i represents which wife is carrying the kitten, j then
sack j of wife i is the mother of the kitten; and l represents the number of the kitten of cat k in
8. (a) 5! = 120
sack j of wife i. By the generalized principle there are thus 7 ⋅ 7 ⋅ 7 ⋅ 7 = 2401 kittens
(d) 4!24 = 384
only one person can be assigned to a job, it follows that the sequence is a permutation of the
represents which of that wife’s 7 sacks contain the kitten; k represents which of the 7 cats in
Problems
9.
2. 64 = 1296
10. (a) 8! = 40,320
다.